Molar Mass of PbI2 (Lead(II) Iodide)

Molar Mass Calculator

What is the molar mass of PbI₂?

Answer

M(PbI₂) =

461.0 g/mol

Atomic weights: IUPAC standard values (CIAAW, 2024).

Contribution of each element
Element	Atoms, n	Atomic weight, A	n × A, g/mol Mass fraction, w	Mass fraction, w
Pblead	1	207.2	207.2 w ≈ 44.95%	≈ 44.95%
Iiodine	2	126.90	253.80 w ≈ 55.05%	≈ 55.05%
Σ = 461.0 g/mol w = 100%				100%

Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

Mass fractions of the elements

I 55.05%Pb 44.95%

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Molar masses of substances nearby

Formula	M, g/mol
AlI₃ (aluminum iodide)	407.68
C₁₂H₂₂CaO₁₄ (calcium gluconate)	430.372
HgI₂ (mercury(II) iodide)	454.39
PbI₂ (lead(II) iodide)	461.0
C₁₆H₉N₄Na₃O₉S₂ (tartrazine)	534.36
Ba₃(PO₄)₂ (barium phosphate)	601.93
C₂₇H₂₈Br₂O₅S (bromthymol blue)	624.38

FAQ

What is the molar mass of PbI2?

M(PbI₂) = 461.0 g/mol

How to calculate the molar mass of PbI₂?

Add up the atomic weights of all the atoms in the formula: 207.2 + 2 × 126.90 = 461.0 g/mol.

How many grams are in 2 moles of PbI₂?

m = n × M = 2 mol × 461.0 g/mol = 922.0 g.

See Also