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    Molar Mass of PbCrO4 (Lead(II) Chromate)

    Molar Mass Calculator
    Chemical formula

    What is the molar mass of PbCrO4?

    Answer

    M(PbCrO4) ≈
    323.2 g/mol

    Atomic weights: IUPAC standard values (CIAAW, 2024); the sum is rounded to the decimal places of the least precise one — Pb: 207.2.

    Contribution of each element
    Element Atoms, n Atomic weight, A n × A, g/mol Mass fraction, w
    Pblead1207.2207.2 w ≈ 64.11%
    Crchromium151.99651.996 w ≈ 16.09%
    Ooxygen415.99963.996 w ≈ 19.80%
    Σ = 323.192 ≈ 323.2 g/mol w = 100%

    Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

    Mass fractions of the elements

    O 19.80%Cr 16.09%

    See Also

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    Molar Mass of PbCrO4 (Lead(II) Chromate): Step by Step. M(PbCrO4) ≈ 323.2 g/mol: 207.2 (Pb) + 51.996 (Cr) + 4 × 15.999 (O). Mass fractions: Pb 64.11%, O 19.80%, Cr 16.09%.
    https://calculat.io/en/other/molar-mass/pbcro4/generated.jpgCopy