Molar Mass of Pb(NO3)2 (Lead(II) Nitrate)
Molar Mass Calculator
What is the molar mass of Pb(NO3)2?
Answer
M(Pb(NO3)2) ≈
331.2 g/mol
Atomic weights: IUPAC standard values (CIAAW, 2024); the sum is rounded to the decimal places of the least precise one — Pb: 207.2.
Pb(NO3)2 = Pb + 2 × (N + 3 O) → Pb 1, N 2, O 6
| Element | Atoms, n | Atomic weight, A | n × A, g/mol Mass fraction, w | |
|---|---|---|---|---|
| Pblead | 1 | 207.2 | 207.2 w ≈ 62.56% | ≈ 62.56% |
| Nnitrogen | 2 | 14.007 | 28.014 w ≈ 8.46% | ≈ 8.46% |
| Ooxygen | 6 | 15.999 | 95.994 w ≈ 28.98% | ≈ 28.98% |
| Σ = 331.208 ≈ 331.2 g/mol w = 100% | 100% | |||
Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)
Pb 62.56%
O 28.98%N 8.46%
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Molar masses of substances nearby
| Formula | M, g/mol |
|---|---|
| Hg(NO₃)₂ (mercuric nitrate) | 324.60 |
| (CH₃COO)₂Pb (lead(II) acetate) | 325.3 |
| CCs₂O₃ (cesium carbonate) | 325.83 |
| Pb(NO₃)₂ (lead(II) nitrate) | 331.2 |
| Al₂(SO₄)₃ (aluminium sulfate) | 342.13 |
| C₁₂H₂₂O₁₁ (sucrose) | 342.297 |
| AgC₁₀H₉N₄SO₂ | 357.14 |