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    Molar Mass of Pb(OH)2 (Lead(II) Hydroxide)

    Molar Mass Calculator
    Chemical formula

    What is the molar mass of Pb(OH)2?

    Answer

    M(Pb(OH)2) ≈
    241.2 g/mol

    Atomic weights: IUPAC standard values (CIAAW, 2024); the sum is rounded to the decimal places of the least precise one — Pb: 207.2.

    Pb(OH)2 = Pb + 2 × (O + H) → Pb 1, O 2, H 2

    Contribution of each element
    Element Atoms, n Atomic weight, A n × A, g/mol Mass fraction, w
    Pblead1207.2207.2 w ≈ 85.90%
    Ooxygen215.99931.998 w ≈ 13.27%
    Hhydrogen21.00802.0160 w ≈ 0.84%
    Σ = 241.214 ≈ 241.2 g/mol w = 100%

    Each fraction is rounded on its own, so the printed ones add up to 100.01%; unrounded, they make exactly 100%.

    Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

    Mass fractions of the elements

    O 13.27%H 0.84%

    See Also

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    <a href="https://calculat.io/en/other/molar-mass/pb%28oh%292">Molar Mass of Pb(OH)2 (Lead(II) Hydroxide): Step by Step</a>Copy
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    Molar Mass of Pb(OH)2 (Lead(II) Hydroxide): Step by Step. M(Pb(OH)2) ≈ 241.2 g/mol: 207.2 (Pb) + 2 × 15.999 (O) + 2 × 1.0080 (H). Mass fractions: Pb 85.90%, O 13.27%, H 0.84%.
    https://calculat.io/en/other/molar-mass/pb%28oh%292/generated.jpgCopy