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    Molar Mass of C16H9N4Na3O9S2 (Tartrazine)

    Molar Mass Calculator
    Chemical formula

    What is the molar mass of C16H9N4Na3O9S2?

    Answer

    M(C16H9N4Na3O9S2) ≈
    534.36 g/mol

    Atomic weights: IUPAC standard values (CIAAW, 2024); the sum is rounded to the decimal places of the least precise one — S: 32.06.

    Contribution of each element
    Element Atoms, n Atomic weight, A n × A, g/mol Mass fraction, w
    Ccarbon1612.011192.176 w ≈ 35.96%
    Hhydrogen91.00809.0720 w ≈ 1.70%
    Nnitrogen414.00756.028 w ≈ 10.49%
    Nasodium322.99068.970 w ≈ 12.91%
    Ooxygen915.999143.991 w ≈ 26.95%
    Ssulfur232.0664.12 w ≈ 12.00%
    Σ = 534.357 ≈ 534.36 g/mol w = 100%

    Each fraction is rounded on its own, so the printed ones add up to 100.01%; unrounded, they make exactly 100%.

    Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

    Mass fractions of the elements

    O 26.95%Na 12.91%S 12.00%N 10.49%H 1.70%

    See Also

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    Molar Mass of C16H9N4Na3O9S2 (Tartrazine): Step by Step. M(C16H9N4Na3O9S2) ≈ 534.36 g/mol. Mass fractions: C 35.96%, O 26.95%, Na 12.91%.
    https://calculat.io/en/other/molar-mass/c16h9n4na3o9s2/generated.jpgCopy

    FAQ

    What is the molar mass of C16H9N4Na3O9S2?

    M(C₁₆H₉N₄Na₃O₉S₂) ≈ 534.36 g/mol

    How to calculate the molar mass of C₁₆H₉N₄Na₃O₉S₂?

    Add up the atomic weights of all the atoms in the formula: 16 × 12.011 + 9 × 1.0080 + 4 × 14.007 + 3 × 22.990 + 9 × 15.999 + 2 × 32.06 = 534.357 ≈ 534.36 g/mol.

    How many grams are in 2 moles of C₁₆H₉N₄Na₃O₉S₂?

    m = n × M = 2 mol × 534.36 g/mol = 1,068.72 g.