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    Molar Mass of PbI2 (Lead(II) Iodide)

    Molar Mass Calculator
    Chemical formula

    What is the molar mass of PbI2?

    Answer

    M(PbI2) =
    461.0 g/mol

    Atomic weights: IUPAC standard values (CIAAW, 2024).

    Contribution of each element
    Element Atoms, n Atomic weight, A n × A, g/mol Mass fraction, w
    Pblead1207.2207.2 w ≈ 44.95%
    Iiodine2126.90253.80 w ≈ 55.05%
    Σ = 461.0 g/mol w = 100%

    Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

    Mass fractions of the elements

    Related Calculations

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    <a href="https://calculat.io/en/other/molar-mass/pbi2">Molar Mass of PbI2 (Lead(II) Iodide): Step by Step</a>Copy
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    Molar Mass of PbI2 (Lead(II) Iodide): Step by Step. M(PbI2) = 461.0 g/mol: 207.2 (Pb) + 2 × 126.90 (I). Mass fractions: I 55.05%, Pb 44.95%.
    https://calculat.io/en/other/molar-mass/pbi2/generated.jpgCopy

    Molar masses of substances nearby

    FormulaM, g/mol
    AlI₃ (aluminum iodide)407.68
    C₁₂H₂₂CaO₁₄ (calcium gluconate)430.372
    HgI₂ (mercury(II) iodide)454.39
    PbI₂ (lead(II) iodide)461.0
    C₁₆H₉N₄Na₃O₉S₂ (tartrazine)534.36
    Ba₃(PO₄)₂ (barium phosphate)601.93
    C₂₇H₂₈Br₂O₅S (bromthymol blue)624.38
    Recalculate with different values ↑

    FAQ

    What is the molar mass of PbI2?

    M(PbI₂) = 461.0 g/mol

    How to calculate the molar mass of PbI₂?

    Add up the atomic weights of all the atoms in the formula: 207.2 + 2 × 126.90 = 461.0 g/mol.

    How many grams are in 2 moles of PbI₂?

    m = n × M = 2 mol × 461.0 g/mol = 922.0 g.

    See Also