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    Molar Mass of AlI3 (Aluminum Iodide)

    Molar Mass Calculator
    Chemical formula

    What is the molar mass of AlI3?

    Answer

    M(AlI3) ≈
    407.68 g/mol

    Atomic weights: IUPAC standard values (CIAAW, 2024); the sum is rounded to the decimal places of the least precise one — I: 126.90.

    Contribution of each element
    Element Atoms, n Atomic weight, A n × A, g/mol Mass fraction, w
    Alaluminium126.98226.982 w ≈ 6.62%
    Iiodine3126.90380.70 w ≈ 93.38%
    Σ = 407.682 ≈ 407.68 g/mol w = 100%

    Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

    Mass fractions of the elements

    Al 6.62%

    Related Calculations

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    <a href="https://calculat.io/en/other/molar-mass/ali3">Molar Mass of AlI3 (Aluminum Iodide): Step by Step</a>Copy
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    Molar Mass of AlI3 (Aluminum Iodide): Step by Step. M(AlI3) ≈ 407.68 g/mol: 26.982 (Al) + 3 × 126.90 (I). Mass fractions: I 93.38%, Al 6.62%.
    https://calculat.io/en/other/molar-mass/ali3/generated.jpgCopy

    Molar masses of substances nearby

    FormulaM, g/mol
    CHI₃ (iodoform)393.72
    C₁₂H₁₉Cl₃O₈ (sucralose)397.63
    Fe₂(SO₄)₃ (ferric sulfate)399.86
    AlI₃ (aluminum iodide)407.68
    C₁₂H₂₂CaO₁₄ (calcium gluconate)430.372
    HgI₂ (mercury(II) iodide)454.39
    PbI₂ (lead(II) iodide)461.0
    Recalculate with different values ↑

    FAQ

    What is the molar mass of AlI3?

    M(AlI₃) ≈ 407.68 g/mol

    How to calculate the molar mass of AlI₃?

    Add up the atomic weights of all the atoms in the formula: 26.982 + 3 × 126.90 = 407.682 ≈ 407.68 g/mol.

    How many grams are in 2 moles of AlI₃?

    m = n × M = 2 mol × 407.68 g/mol = 815.36 g.

    See Also