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    Molar Mass of PbS (Lead(II) Sulfide)

    Molar Mass Calculator
    Chemical formula

    What is the molar mass of PbS?

    Answer

    M(PbS) ≈
    239.3 g/mol

    Atomic weights: IUPAC standard values (CIAAW, 2024); the sum is rounded to the decimal places of the least precise one — Pb: 207.2.

    Contribution of each element
    Element Atoms, n Atomic weight, A n × A, g/mol Mass fraction, w
    Pblead1207.2207.2 w ≈ 86.60%
    Ssulfur132.0632.06 w ≈ 13.40%
    Σ = 239.26 ≈ 239.3 g/mol w = 100%

    Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

    Mass fractions of the elements

    S 13.40%

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    Molar Mass of PbS (Lead(II) Sulfide): Step by Step. M(PbS) ≈ 239.3 g/mol: 207.2 (Pb) + 32.06 (S). Mass fractions: Pb 86.60%, S 13.40%.
    https://calculat.io/en/other/molar-mass/pbs/generated.jpgCopy

    Molar masses of substances nearby

    FormulaM, g/mol
    CdN₂O₆ (cadmium nitrate)236.42
    U (uranium)238.03
    PbO₂ (lead dioxide)239.2
    PbS (lead(II) sulfide)239.3
    Pb(OH)₂ (lead(II) hydroxide)241.2
    Fe(NO₃)₃ (ferric nitrate)241.857
    BaCl₂·2H₂O (barium chloride dihydrate)244.26
    Recalculate with different values ↑

    FAQ

    What is the molar mass of PbS?

    M(PbS) ≈ 239.3 g/mol

    How to calculate the molar mass of PbS?

    Add up the atomic weights of all the atoms in the formula: 207.2 + 32.06 = 239.26 ≈ 239.3 g/mol.

    How many grams are in 2 moles of PbS?

    m = n × M = 2 mol × 239.3 g/mol = 478.6 g.

    See Also