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    Molar Mass of C27H28Br2O5S (Bromthymol Blue)

    Molar Mass Calculator
    Chemical formula

    What is the molar mass of C27H28Br2O5S?

    Answer

    M(C27H28Br2O5S) ≈
    624.38 g/mol

    Atomic weights: IUPAC standard values (CIAAW, 2024); the sum is rounded to the decimal places of the least precise one — S: 32.06.

    Contribution of each element
    Element Atoms, n Atomic weight, A n × A, g/mol Mass fraction, w
    Ccarbon2712.011324.297 w ≈ 51.94%
    Hhydrogen281.008028.2240 w ≈ 4.52%
    Brbromine279.904159.808 w ≈ 25.59%
    Ooxygen515.99979.995 w ≈ 12.81%
    Ssulfur132.0632.06 w ≈ 5.13%
    Σ = 624.384 ≈ 624.38 g/mol w = 100%

    Each fraction is rounded on its own, so the printed ones add up to 99.99%; unrounded, they make exactly 100%.

    Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

    Mass fractions of the elements

    Br 25.59%O 12.81%S 5.13%H 4.52%

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    Molar Mass of C27H28Br2O5S (Bromthymol Blue): Step by Step. M(C27H28Br2O5S) ≈ 624.38 g/mol: 27 × 12.011 (C) + 28 × 1.0080 (H) + 2 × 79.904 (Br) + 5 × 15.999 (O) + 32.06 (S). Mass fractions: C 51.94%, Br 25.59%, O 12.81%.
    https://calculat.io/en/other/molar-mass/c27h28br2o5s/generated.jpgCopy

    FAQ

    What is the molar mass of C27H28Br2O5S?

    M(C₂₇H₂₈Br₂O₅S) ≈ 624.38 g/mol

    How to calculate the molar mass of C₂₇H₂₈Br₂O₅S?

    Add up the atomic weights of all the atoms in the formula: 27 × 12.011 + 28 × 1.0080 + 2 × 79.904 + 5 × 15.999 + 32.06 = 624.384 ≈ 624.38 g/mol.

    How many grams are in 2 moles of C₂₇H₂₈Br₂O₅S?

    m = n × M = 2 mol × 624.38 g/mol = 1,248.76 g.