Molar Mass of Ba3(PO4)2 (Barium Phosphate)
Molar Mass Calculator
What is the molar mass of Ba3(PO4)2?
Answer
M(Ba3(PO4)2) =
601.93 g/mol
Atomic weights: IUPAC standard values (CIAAW, 2024).
Ba3(PO4)2 = 3 Ba + 2 × (P + 4 O) → Ba 3, P 2, O 8
| Element | Atoms, n | Atomic weight, A | n × A, g/mol Mass fraction, w | |
|---|---|---|---|---|
| Babarium | 3 | 137.33 | 411.99 w ≈ 68.44% | ≈ 68.44% |
| Pphosphorus | 2 | 30.974 | 61.948 w ≈ 10.29% | ≈ 10.29% |
| Ooxygen | 8 | 15.999 | 127.992 w ≈ 21.26% | ≈ 21.26% |
| Σ = 601.93 g/mol w = 100% | 100% | |||
Each fraction is rounded on its own, so the printed ones add up to 99.99%; unrounded, they make exactly 100%.
Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)
Ba 68.44%
O 21.26%P 10.29%
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