Molar Mass of Mg3(PO4)2 (Magnesium Phosphate)
Molar Mass Calculator
What is the molar mass of Mg3(PO4)2?
Answer
M(Mg3(PO4)2) =
262.855 g/mol
Atomic weights: IUPAC standard values (CIAAW, 2024).
Mg3(PO4)2 = 3 Mg + 2 × (P + 4 O) → Mg 3, P 2, O 8
| Element | Atoms, n | Atomic weight, A | n × A, g/mol Mass fraction, w | |
|---|---|---|---|---|
| Mgmagnesium | 3 | 24.305 | 72.915 w ≈ 27.74% | ≈ 27.74% |
| Pphosphorus | 2 | 30.974 | 61.948 w ≈ 23.57% | ≈ 23.57% |
| Ooxygen | 8 | 15.999 | 127.992 w ≈ 48.69% | ≈ 48.69% |
| Σ = 262.855 g/mol w = 100% | 100% | |||
Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)
O 48.69%
Mg 27.74%P 23.57%
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Molar masses of substances nearby
| Formula | M, g/mol |
|---|---|
| C₆H₅Na₃O₇ (trisodium citrate) | 258.069 |
| Ba(NO₃)₂ (barium nitrate) | 261.34 |
| Na₂Cr₂O₇ (sodium dichromate) | 261.965 |
| Mg₃(PO₄)₂ (magnesium phosphate) | 262.855 |
| AlBr₃ (aluminum bromide) | 266.694 |
| PbCO₃ (lead carbonate) | 267.2 |
| HgCl₂ (mercuric chloride) | 271.49 |