Feedback form
Hi! What do you think?

Drag it here or paste with Ctrl+V


    You can also email us on infocalculat.io

    Molar Mass of MgBr2 (Magnesium Bromide)

    Molar Mass Calculator
    Chemical formula

    What is the molar mass of MgBr2?

    Answer

    M(MgBr2) =
    184.113 g/mol

    Atomic weights: IUPAC standard values (CIAAW, 2024).

    Contribution of each element
    Element Atoms, n Atomic weight, A n × A, g/mol Mass fraction, w
    Mgmagnesium124.30524.305 w ≈ 13.20%
    Brbromine279.904159.808 w ≈ 86.80%
    Σ = 184.113 g/mol w = 100%

    Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

    Mass fractions of the elements

    Mg 13.20%

    See Also

    Share This Calculation
    Print
    https://calculat.io/en/other/molar-mass/mgbr2Copy
    <a href="https://calculat.io/en/other/molar-mass/mgbr2">Molar Mass of MgBr2 (Magnesium Bromide): Step by Step</a>Copy
    Facebook
    Twitter
    Telegram
    WhatsApp
    Viber
    Email
    Molar Mass of MgBr2 (Magnesium Bromide): Step by Step. M(MgBr2) = 184.113 g/mol: 24.305 (Mg) + 2 × 79.904 (Br). Mass fractions: Br 86.80%, Mg 13.20%.
    https://calculat.io/en/other/molar-mass/mgbr2/generated.jpgCopy

    FAQ

    What is the molar mass of MgBr2?

    M(MgBr₂) = 184.113 g/mol

    How to calculate the molar mass of MgBr₂?

    Add up the atomic weights of all the atoms in the formula: 24.305 + 2 × 79.904 = 184.113 g/mol.

    How many grams are in 2 moles of MgBr₂?

    m = n × M = 2 mol × 184.113 g/mol = 368.226 g.