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    Molar Mass of AlBr3 (Aluminum Bromide)

    Molar Mass Calculator
    Chemical formula

    What is the molar mass of AlBr3?

    Answer

    M(AlBr3) =
    266.694 g/mol

    Atomic weights: IUPAC standard values (CIAAW, 2024).

    Contribution of each element
    Element Atoms, n Atomic weight, A n × A, g/mol Mass fraction, w
    Alaluminium126.98226.982 w ≈ 10.12%
    Brbromine379.904239.712 w ≈ 89.88%
    Σ = 266.694 g/mol w = 100%

    Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

    Mass fractions of the elements

    Al 10.12%

    Related Calculations

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    <a href="https://calculat.io/en/other/molar-mass/albr3">Molar Mass of AlBr3 (Aluminum Bromide): Step by Step</a>Copy
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    Molar Mass of AlBr3 (Aluminum Bromide): Step by Step. M(AlBr3) = 266.694 g/mol: 26.982 (Al) + 3 × 79.904 (Br). Mass fractions: Br 89.88%, Al 10.12%.
    https://calculat.io/en/other/molar-mass/albr3/generated.jpgCopy

    Molar masses of substances nearby

    FormulaM, g/mol
    Ba(NO₃)₂ (barium nitrate)261.34
    Na₂Cr₂O₇ (sodium dichromate)261.965
    Mg₃(PO₄)₂ (magnesium phosphate)262.855
    AlBr₃ (aluminum bromide)266.694
    PbCO₃ (lead carbonate)267.2
    HgCl₂ (mercuric chloride)271.49
    Ag₂CO₃ (silver carbonate)275.75
    Recalculate with different values ↑

    FAQ

    What is the molar mass of AlBr3?

    M(AlBr₃) = 266.694 g/mol

    How to calculate the molar mass of AlBr₃?

    Add up the atomic weights of all the atoms in the formula: 26.982 + 3 × 79.904 = 266.694 g/mol.

    How many grams are in 2 moles of AlBr₃?

    m = n × M = 2 mol × 266.694 g/mol = 533.388 g.

    See Also