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    Molar Mass of MgF2 (Magnesium Fluoride)

    Molar Mass Calculator
    Chemical formula

    What is the molar mass of MgF2?

    Answer

    M(MgF2) =
    62.301 g/mol

    Atomic weights: IUPAC standard values (CIAAW, 2024).

    Contribution of each element
    Element Atoms, n Atomic weight, A n × A, g/mol Mass fraction, w
    Mgmagnesium124.30524.305 w ≈ 39.01%
    Ffluorine218.99837.996 w ≈ 60.99%
    Σ = 62.301 g/mol w = 100%

    Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

    Mass fractions of the elements

    See Also

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    <a href="https://calculat.io/en/other/molar-mass/mgf2">Molar Mass of MgF2 (Magnesium Fluoride): Step by Step</a>Copy
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    Molar Mass of MgF2 (Magnesium Fluoride): Step by Step. M(MgF2) = 62.301 g/mol: 24.305 (Mg) + 2 × 18.998 (F). Mass fractions: F 60.99%, Mg 39.01%.
    https://calculat.io/en/other/molar-mass/mgf2/generated.jpgCopy

    FAQ

    What is the molar mass of MgF2?

    M(MgF₂) = 62.301 g/mol

    How to calculate the molar mass of MgF₂?

    Add up the atomic weights of all the atoms in the formula: 24.305 + 2 × 18.998 = 62.301 g/mol.

    How many grams are in 2 moles of MgF₂?

    m = n × M = 2 mol × 62.301 g/mol = 124.602 g.