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    Molar Mass of C6H5Na3O7 (Trisodium Citrate)

    Molar Mass Calculator
    Chemical formula

    What is the molar mass of C6H5Na3O7?

    Answer

    M(C6H5Na3O7) =
    258.069 g/mol

    Atomic weights: IUPAC standard values (CIAAW, 2024).

    Contribution of each element
    Element Atoms, n Atomic weight, A n × A, g/mol Mass fraction, w
    Ccarbon612.01172.066 w ≈ 27.93%
    Hhydrogen51.00805.0400 w ≈ 1.95%
    Nasodium322.99068.970 w ≈ 26.73%
    Ooxygen715.999111.993 w ≈ 43.40%
    Σ = 258.069 g/mol w = 100%

    Each fraction is rounded on its own, so the printed ones add up to 100.01%; unrounded, they make exactly 100%.

    Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

    Mass fractions of the elements

    C 27.93%Na 26.73%H 1.95%

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    <a href="https://calculat.io/en/other/molar-mass/c6h5na3o7">Molar Mass of C6H5Na3O7 (Trisodium Citrate): Step by Step</a>Copy
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    Molar Mass of C6H5Na3O7 (Trisodium Citrate): Step by Step. M(C6H5Na3O7) = 258.069 g/mol: 6 × 12.011 (C) + 5 × 1.0080 (H) + 3 × 22.990 (Na) + 7 × 15.999 (O). Mass fractions: O 43.40%, C 27.93%, Na 26.73%.
    https://calculat.io/en/other/molar-mass/c6h5na3o7/generated.jpgCopy

    FAQ

    What is the molar mass of C6H5Na3O7?

    M(C₆H₅Na₃O₇) = 258.069 g/mol

    How to calculate the molar mass of C₆H₅Na₃O₇?

    Add up the atomic weights of all the atoms in the formula: 6 × 12.011 + 5 × 1.0080 + 3 × 22.990 + 7 × 15.999 = 258.069 g/mol.

    How many grams are in 2 moles of C₆H₅Na₃O₇?

    m = n × M = 2 mol × 258.069 g/mol = 516.138 g.