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    Molar Mass of MgCO3 (Magnesium Carbonate)

    Molar Mass Calculator
    Chemical formula

    What is the molar mass of MgCO3?

    Answer

    M(MgCO3) =
    84.313 g/mol

    Atomic weights: IUPAC standard values (CIAAW, 2024).

    Contribution of each element
    Element Atoms, n Atomic weight, A n × A, g/mol Mass fraction, w
    Mgmagnesium124.30524.305 w ≈ 28.83%
    Ccarbon112.01112.011 w ≈ 14.25%
    Ooxygen315.99947.997 w ≈ 56.93%
    Σ = 84.313 g/mol w = 100%

    Each fraction is rounded on its own, so the printed ones add up to 100.01%; unrounded, they make exactly 100%.

    Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

    Mass fractions of the elements

    Mg 28.83%C 14.25%

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    Molar Mass of MgCO3 (Magnesium Carbonate): Step by Step. M(MgCO3) = 84.313 g/mol: 24.305 (Mg) + 12.011 (C) + 3 × 15.999 (O). Mass fractions: O 56.93%, Mg 28.83%, C 14.25%.
    https://calculat.io/en/other/molar-mass/mgco3/generated.jpgCopy

    FAQ

    What is the molar mass of MgCO3?

    M(MgCO₃) = 84.313 g/mol

    How to calculate the molar mass of MgCO₃?

    Add up the atomic weights of all the atoms in the formula: 24.305 + 12.011 + 3 × 15.999 = 84.313 g/mol.

    How many grams are in 2 moles of MgCO₃?

    m = n × M = 2 mol × 84.313 g/mol = 168.626 g.