Molar Mass of Mg(NO3)2 (Magnesium Nitrate)
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What is the molar mass of Mg(NO3)2?
Answer
M(Mg(NO3)2) =
148.313 g/mol
Atomic weights: IUPAC standard values (CIAAW, 2024).
Mg(NO3)2 = Mg + 2 × (N + 3 O) → Mg 1, N 2, O 6
| Element | Atoms, n | Atomic weight, A | n × A, g/mol Mass fraction, w | |
|---|---|---|---|---|
| Mgmagnesium | 1 | 24.305 | 24.305 w ≈ 16.39% | ≈ 16.39% |
| Nnitrogen | 2 | 14.007 | 28.014 w ≈ 18.89% | ≈ 18.89% |
| Ooxygen | 6 | 15.999 | 95.994 w ≈ 64.72% | ≈ 64.72% |
| Σ = 148.313 g/mol w = 100% | 100% | |||
Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)
O 64.72%
N 18.89%Mg 16.39%
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Molar masses of substances nearby
| Formula | M, g/mol |
|---|---|
| SrCO₃ (strontium carbonate) | 147.63 |
| C₈H₄O₃ (phthalic anhydride) | 148.117 |
| C₉H₈O₂ ((E)-cinnamic acid) | 148.161 |
| Mg(NO₃)₂ (magnesium nitrate) | 148.313 |
| C₅H₁₁NO₂S (DL-methionine) | 149.21 |
| AgOCN (silver cyanate) | 149.89 |
| NaI (sodium iodide) | 149.89 |