Molar Mass of Ba(NO3)2 (Barium Nitrate)
Molar Mass Calculator
What is the molar mass of Ba(NO3)2?
Answer
M(Ba(NO3)2) ≈
261.34 g/mol
Atomic weights: IUPAC standard values (CIAAW, 2024); the sum is rounded to the decimal places of the least precise one — Ba: 137.33.
Ba(NO3)2 = Ba + 2 × (N + 3 O) → Ba 1, N 2, O 6
| Element | Atoms, n | Atomic weight, A | n × A, g/mol Mass fraction, w | |
|---|---|---|---|---|
| Babarium | 1 | 137.33 | 137.33 w ≈ 52.55% | ≈ 52.55% |
| Nnitrogen | 2 | 14.007 | 28.014 w ≈ 10.72% | ≈ 10.72% |
| Ooxygen | 6 | 15.999 | 95.994 w ≈ 36.73% | ≈ 36.73% |
| Σ = 261.338 ≈ 261.34 g/mol w = 100% | 100% | |||
Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)
Ba 52.55%O 36.73%
N 10.72%
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Molar masses of substances nearby
| Formula | M, g/mol |
|---|---|
| I₂ (iodine) | 253.80 |
| S₈ (octasulfur) | 256.48 |
| C₆H₅Na₃O₇ (trisodium citrate) | 258.069 |
| Ba(NO₃)₂ (barium nitrate) | 261.34 |
| Na₂Cr₂O₇ (sodium dichromate) | 261.965 |
| Mg₃(PO₄)₂ (magnesium phosphate) | 262.855 |
| AlBr₃ (aluminum bromide) | 266.694 |