Molar Mass of C11H12N2O2 (Tryptophan)
Molar Mass Calculator
What is the molar mass of C11H12N2O2?
Answer
M(C11H12N2O2) =
204.229 g/mol
Atomic weights: IUPAC standard values (CIAAW, 2024).
| Element | Atoms, n | Atomic weight, A | n × A, g/mol Mass fraction, w | |
|---|---|---|---|---|
| Ccarbon | 11 | 12.011 | 132.121 w ≈ 64.69% | ≈ 64.69% |
| Hhydrogen | 12 | 1.0080 | 12.0960 w ≈ 5.92% | ≈ 5.92% |
| Nnitrogen | 2 | 14.007 | 28.014 w ≈ 13.72% | ≈ 13.72% |
| Ooxygen | 2 | 15.999 | 31.998 w ≈ 15.67% | ≈ 15.67% |
| Σ = 204.229 g/mol w = 100% | 100% | |||
Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)
C 64.69%
O 15.67%N 13.72%H 5.92%
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Molar masses of substances nearby
| Formula | M, g/mol |
|---|---|
| Hg (mercury) | 200.59 |
| Na₂B₄O₇ | 201.21 |
| C₁₀H₁₈O₄ (sebacic acid) | 202.250 |
| C₁₁H₁₂N₂O₂ (tryptophan) | 204.229 |
| Tl (thallium) | 204.38 |
| Ca(ClO₃)₂ (calcium chlorate) | 206.97 |
| Pb (lead) | 207.2 |
FAQ
What is the molar mass of C11H12N2O2?
M(C₁₁H₁₂N₂O₂) = 204.229 g/mol
How to calculate the molar mass of C₁₁H₁₂N₂O₂?
Add up the atomic weights of all the atoms in the formula: 11 × 12.011 + 12 × 1.0080 + 2 × 14.007 + 2 × 15.999 = 204.229 g/mol.
How many grams are in 2 moles of C₁₁H₁₂N₂O₂?
m = n × M = 2 mol × 204.229 g/mol = 408.458 g.
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