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    Molar Mass of C9H8O4 (Aspirin)

    Molar Mass Calculator
    Chemical formula

    What is the molar mass of C9H8O4?

    Answer

    M(C9H8O4) =
    180.159 g/mol

    Atomic weights: IUPAC standard values (CIAAW, 2024).

    Contribution of each element
    Element Atoms, n Atomic weight, A n × A, g/mol Mass fraction, w
    Ccarbon912.011108.099 w ≈ 60.00%
    Hhydrogen81.00808.0640 w ≈ 4.48%
    Ooxygen415.99963.996 w ≈ 35.52%
    Σ = 180.159 g/mol w = 100%

    Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

    Mass fractions of the elements

    H 4.48%

    Related Calculations

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    Molar Mass of C9H8O4 (Aspirin): Step by Step. M(C9H8O4) = 180.159 g/mol: 9 × 12.011 (C) + 8 × 1.0080 (H) + 4 × 15.999 (O). Mass fractions: C 60.00%, O 35.52%, H 4.48%.
    https://calculat.io/en/other/molar-mass/c9h8o4/generated.jpgCopy

    Molar masses of substances nearby

    FormulaM, g/mol
    Hf (hafnium)178.49
    Mn(NO₃)₂ (manganese nitrate)178.946
    C₆H₁₂O₆ (glucose)180.156
    C₉H₈O₄ (aspirin)180.159
    Ta (tantalum)180.95
    (CH₃COO)₂Cu (copper(II) acetate)181.634
    V₂O₅ (vanadium(V) oxide)181.879
    Recalculate with different values ↑

    FAQ

    What is the molar mass of C9H8O4?

    M(C₉H₈O₄) = 180.159 g/mol

    How to calculate the molar mass of C₉H₈O₄?

    Add up the atomic weights of all the atoms in the formula: 9 × 12.011 + 8 × 1.0080 + 4 × 15.999 = 180.159 g/mol.

    How many grams are in 2 moles of C₉H₈O₄?

    m = n × M = 2 mol × 180.159 g/mol = 360.318 g.

    See Also