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    Molar Mass of C10H18O4 (Sebacic Acid)

    Molar Mass Calculator
    Chemical formula

    What is the molar mass of C10H18O4?

    Answer

    M(C10H18O4) =
    202.250 g/mol

    Atomic weights: IUPAC standard values (CIAAW, 2024).

    Contribution of each element
    Element Atoms, n Atomic weight, A n × A, g/mol Mass fraction, w
    Ccarbon1012.011120.110 w ≈ 59.39%
    Hhydrogen181.008018.1440 w ≈ 8.97%
    Ooxygen415.99963.996 w ≈ 31.64%
    Σ = 202.250 g/mol w = 100%

    Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

    Mass fractions of the elements

    O 31.64%H 8.97%

    Related Calculations

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    <a href="https://calculat.io/en/other/molar-mass/c10h18o4">Molar Mass of C10H18O4 (Sebacic Acid): Step by Step</a>Copy
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    Molar Mass of C10H18O4 (Sebacic Acid): Step by Step. M(C10H18O4) = 202.250 g/mol: 10 × 12.011 (C) + 18 × 1.0080 (H) + 4 × 15.999 (O). Mass fractions: C 59.39%, O 31.64%, H 8.97%.
    https://calculat.io/en/other/molar-mass/c10h18o4/generated.jpgCopy

    Molar masses of substances nearby

    FormulaM, g/mol
    CaBr₂ (calcium bromide)199.886
    Hg (mercury)200.59
    Na₂B₄O₇201.21
    C₁₀H₁₈O₄ (sebacic acid)202.250
    C₁₁H₁₂N₂O₂ (tryptophan)204.229
    Tl (thallium)204.38
    Ca(ClO₃)₂ (calcium chlorate)206.97
    Recalculate with different values ↑

    FAQ

    What is the molar mass of C10H18O4?

    M(C₁₀H₁₈O₄) = 202.250 g/mol

    How to calculate the molar mass of C₁₀H₁₈O₄?

    Add up the atomic weights of all the atoms in the formula: 10 × 12.011 + 18 × 1.0080 + 4 × 15.999 = 202.250 g/mol.

    How many grams are in 2 moles of C₁₀H₁₈O₄?

    m = n × M = 2 mol × 202.250 g/mol = 404.500 g.

    See Also