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    Molar Mass of Na2B4O7

    Molar Mass Calculator
    Chemical formula

    What is the molar mass of Na2B4O7?

    Answer

    M(Na2B4O7) ≈
    201.21 g/mol

    Atomic weights: IUPAC standard values (CIAAW, 2024); the sum is rounded to the decimal places of the least precise one — B: 10.81.

    Contribution of each element
    Element Atoms, n Atomic weight, A n × A, g/mol Mass fraction, w
    Nasodium222.99045.980 w ≈ 22.85%
    Bboron410.8143.24 w ≈ 21.49%
    Ooxygen715.999111.993 w ≈ 55.66%
    Σ = 201.213 ≈ 201.21 g/mol w = 100%

    Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

    Mass fractions of the elements

    Na 22.85%B 21.49%

    Related Calculations

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    Molar Mass of Na2B4O7: Step by Step. M(Na2B4O7) ≈ 201.21 g/mol: 2 × 22.990 (Na) + 4 × 10.81 (B) + 7 × 15.999 (O). Mass fractions: O 55.66%, Na 22.85%, B 21.49%.
    https://calculat.io/en/other/molar-mass/na2b4o7/generated.jpgCopy

    Molar masses of substances nearby

    FormulaM, g/mol
    NaC₆H₇O₆ (sodium ascorbate)198.106
    CaBr₂ (calcium bromide)199.886
    Hg (mercury)200.59
    Na₂B₄O₇201.21
    C₁₀H₁₈O₄ (sebacic acid)202.250
    C₁₁H₁₂N₂O₂ (tryptophan)204.229
    Tl (thallium)204.38
    Recalculate with different values ↑

    FAQ

    What is the molar mass of Na2B4O7?

    M(Na₂B₄O₇) ≈ 201.21 g/mol

    How to calculate the molar mass of Na₂B₄O₇?

    Add up the atomic weights of all the atoms in the formula: 2 × 22.990 + 4 × 10.81 + 7 × 15.999 = 201.213 ≈ 201.21 g/mol.

    How many grams are in 2 moles of Na₂B₄O₇?

    m = n × M = 2 mol × 201.21 g/mol = 402.42 g.

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