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    Molar Mass of C12H25NaO4S (Sodium Lauryl Sulfate)

    Molar Mass Calculator
    Chemical formula

    What is the molar mass of C12H25NaO4S?

    Answer

    M(C12H25NaO4S) ≈
    288.38 g/mol

    Atomic weights: IUPAC standard values (CIAAW, 2024); the sum is rounded to the decimal places of the least precise one — S: 32.06.

    Contribution of each element
    Element Atoms, n Atomic weight, A n × A, g/mol Mass fraction, w
    Ccarbon1212.011144.132 w ≈ 49.98%
    Hhydrogen251.008025.2000 w ≈ 8.74%
    Nasodium122.99022.990 w ≈ 7.97%
    Ooxygen415.99963.996 w ≈ 22.19%
    Ssulfur132.0632.06 w ≈ 11.12%
    Σ = 288.378 ≈ 288.38 g/mol w = 100%

    Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

    Mass fractions of the elements

    O 22.19%S 11.12%H 8.74%Na 7.97%

    See Also

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    Molar Mass of C12H25NaO4S (Sodium Lauryl Sulfate). M(C12H25NaO4S) ≈ 288.38 g/mol: 12 × 12.011 (C) + 25 × 1.0080 (H) + 22.990 (Na) + 4 × 15.999 (O) + 32.06 (S). Mass fractions: C 49.98%, O 22.19%, S 11.12%.
    https://calculat.io/en/other/molar-mass/c12h25nao4s/generated.jpgCopy

    FAQ

    What is the molar mass of C12H25NaO4S?

    M(C₁₂H₂₅NaO₄S) ≈ 288.38 g/mol

    How to calculate the molar mass of C₁₂H₂₅NaO₄S?

    Add up the atomic weights of all the atoms in the formula: 12 × 12.011 + 25 × 1.0080 + 22.990 + 4 × 15.999 + 32.06 = 288.378 ≈ 288.38 g/mol.

    How many grams are in 2 moles of C₁₂H₂₅NaO₄S?

    m = n × M = 2 mol × 288.38 g/mol = 576.76 g.