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    Molar Mass of C10H16N2O3S (Biotin)

    Molar Mass Calculator
    Chemical formula

    What is the molar mass of C10H16N2O3S?

    Answer

    M(C10H16N2O3S) ≈
    244.31 g/mol

    Atomic weights: IUPAC standard values (CIAAW, 2024); the sum is rounded to the decimal places of the least precise one — S: 32.06.

    Contribution of each element
    Element Atoms, n Atomic weight, A n × A, g/mol Mass fraction, w
    Ccarbon1012.011120.110 w ≈ 49.16%
    Hhydrogen161.008016.1280 w ≈ 6.60%
    Nnitrogen214.00728.014 w ≈ 11.47%
    Ooxygen315.99947.997 w ≈ 19.65%
    Ssulfur132.0632.06 w ≈ 13.12%
    Σ = 244.309 ≈ 244.31 g/mol w = 100%

    Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

    Mass fractions of the elements

    O 19.65%S 13.12%N 11.47%H 6.60%

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    <a href="https://calculat.io/en/other/molar-mass/c10h16n2o3s">Molar Mass of C10H16N2O3S (Biotin): Step by Step</a>Copy
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    Molar Mass of C10H16N2O3S (Biotin): Step by Step. M(C10H16N2O3S) ≈ 244.31 g/mol: 10 × 12.011 (C) + 16 × 1.0080 (H) + 2 × 14.007 (N) + 3 × 15.999 (O) + 32.06 (S). Mass fractions: C 49.16%, O 19.65%, S 13.12%.
    https://calculat.io/en/other/molar-mass/c10h16n2o3s/generated.jpgCopy

    FAQ

    What is the molar mass of C10H16N2O3S?

    M(C₁₀H₁₆N₂O₃S) ≈ 244.31 g/mol

    How to calculate the molar mass of C₁₀H₁₆N₂O₃S?

    Add up the atomic weights of all the atoms in the formula: 10 × 12.011 + 16 × 1.0080 + 2 × 14.007 + 3 × 15.999 + 32.06 = 244.309 ≈ 244.31 g/mol.

    How many grams are in 2 moles of C₁₀H₁₆N₂O₃S?

    m = n × M = 2 mol × 244.31 g/mol = 488.62 g.