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    Molar Mass of C10H14N2 ((−)-nicotine)

    Molar Mass Calculator
    Chemical formula

    What is the molar mass of C10H14N2?

    Answer

    M(C10H14N2) =
    162.236 g/mol

    Atomic weights: IUPAC standard values (CIAAW, 2024).

    Contribution of each element
    Element Atoms, n Atomic weight, A n × A, g/mol Mass fraction, w
    Ccarbon1012.011120.110 w ≈ 74.03%
    Hhydrogen141.008014.1120 w ≈ 8.70%
    Nnitrogen214.00728.014 w ≈ 17.27%
    Σ = 162.236 g/mol w = 100%

    Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

    Mass fractions of the elements

    N 17.27%H 8.70%

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    Molar Mass of C10H14N2 ((−)-nicotine): Step by Step. M(C10H14N2) = 162.236 g/mol: 10 × 12.011 (C) + 14 × 1.0080 (H) + 2 × 14.007 (N). Mass fractions: C 74.03%, N 17.27%, H 8.70%.
    https://calculat.io/en/other/molar-mass/c10h14n2/generated.jpgCopy

    Molar masses of substances nearby

    FormulaM, g/mol
    Na₂CrO₄ (sodium chromate)161.972
    Ca(HCO₃)₂ (calcium bicarbonate)162.110
    FeCl₃ (ferric chloride)162.20
    C₁₀H₁₄N₂ ((−)-nicotine)162.236
    C₆H₁₀OS₂ (allicin)162.27
    Dy (dysprosium)162.50
    Na₃PO₄ (trisodium phosphate)163.940
    Recalculate with different values ↑

    FAQ

    What is the molar mass of C10H14N2?

    M(C₁₀H₁₄N₂) = 162.236 g/mol

    How to calculate the molar mass of C₁₀H₁₄N₂?

    Add up the atomic weights of all the atoms in the formula: 10 × 12.011 + 14 × 1.0080 + 2 × 14.007 = 162.236 g/mol.

    How many grams are in 2 moles of C₁₀H₁₄N₂?

    m = n × M = 2 mol × 162.236 g/mol = 324.472 g.

    See Also