Molar Mass of C10H16N2O3S (Biotin)

Molar Mass Calculator

What is the molar mass of C₁₀H₁₆N₂O₃S?

Answer

M(C₁₀H₁₆N₂O₃S) ≈

244.31 g/mol

Atomic weights: IUPAC standard values (CIAAW, 2024); the sum is rounded to the decimal places of the least precise one — S: 32.06.

Contribution of each element
Element	Atoms, n	Atomic weight, A	n × A, g/mol Mass fraction, w	Mass fraction, w
Ccarbon	10	12.011	120.110 w ≈ 49.16%	≈ 49.16%
Hhydrogen	16	1.0080	16.1280 w ≈ 6.60%	≈ 6.60%
Nnitrogen	2	14.007	28.014 w ≈ 11.47%	≈ 11.47%
Ooxygen	3	15.999	47.997 w ≈ 19.65%	≈ 19.65%
Ssulfur	1	32.06	32.06 w ≈ 13.12%	≈ 13.12%
Σ = 244.309 ≈ 244.31 g/mol w = 100%				100%

Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

Mass fractions of the elements

C 49.16%

O 19.65%S 13.12%N 11.47%H 6.60%

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Molar masses of substances nearby

Formula	M, g/mol
Pb(OH)₂ (lead(II) hydroxide)	241.2
Fe(NO₃)₃ (ferric nitrate)	241.857
BaCl₂·2H₂O (barium chloride dihydrate)	244.26
C₁₀H₁₆N₂O₃S (biotin)	244.31
MgSO₄·7H₂O (magnesium sulfate heptahydrate)	246.47
Ag₂S (silver sulfide)	247.80
CuSO₄·5H₂O (copper(II) sulfate pentahydrate)	249.68

FAQ

What is the molar mass of C10H16N2O3S?

M(C₁₀H₁₆N₂O₃S) ≈ 244.31 g/mol

How to calculate the molar mass of C₁₀H₁₆N₂O₃S?

Add up the atomic weights of all the atoms in the formula: 10 × 12.011 + 16 × 1.0080 + 2 × 14.007 + 3 × 15.999 + 32.06 = 244.309 ≈ 244.31 g/mol.

How many grams are in 2 moles of C₁₀H₁₆N₂O₃S?

m = n × M = 2 mol × 244.31 g/mol = 488.62 g.

See Also