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    Molar Mass of Ag2S (Silver Sulfide)

    Molar Mass Calculator
    Chemical formula

    What is the molar mass of Ag2S?

    Answer

    M(Ag2S) =
    247.80 g/mol

    Atomic weights: IUPAC standard values (CIAAW, 2024).

    Contribution of each element
    Element Atoms, n Atomic weight, A n × A, g/mol Mass fraction, w
    Agsilver2107.87215.74 w ≈ 87.06%
    Ssulfur132.0632.06 w ≈ 12.94%
    Σ = 247.80 g/mol w = 100%

    Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

    Mass fractions of the elements

    S 12.94%

    Related Calculations

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    <a href="https://calculat.io/en/other/molar-mass/ag2s">Molar Mass of Ag2S (Silver Sulfide): Step by Step</a>Copy
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    Molar Mass of Ag2S (Silver Sulfide): Step by Step. M(Ag2S) = 247.80 g/mol: 2 × 107.87 (Ag) + 32.06 (S). Mass fractions: Ag 87.06%, S 12.94%.
    https://calculat.io/en/other/molar-mass/ag2s/generated.jpgCopy

    Molar masses of substances nearby

    FormulaM, g/mol
    BaCl₂·2H₂O (barium chloride dihydrate)244.26
    C₁₀H₁₆N₂O₃S (biotin)244.31
    MgSO₄·7H₂O (magnesium sulfate heptahydrate)246.47
    Ag₂S (silver sulfide)247.80
    CuSO₄·5H₂O (copper(II) sulfate pentahydrate)249.68
    (NH₄)₂Cr₂O₇ (ammonium dichromate)252.063
    BaCrO₄ (barium chromate)253.32
    Recalculate with different values ↑

    FAQ

    What is the molar mass of Ag2S?

    M(Ag₂S) = 247.80 g/mol

    How to calculate the molar mass of Ag₂S?

    Add up the atomic weights of all the atoms in the formula: 2 × 107.87 + 32.06 = 247.80 g/mol.

    How many grams are in 2 moles of Ag₂S?

    m = n × M = 2 mol × 247.80 g/mol = 495.60 g.

    See Also