Molar Mass of Ba(NO3)2 (Barium Nitrate)

Molar Mass Calculator

What is the molar mass of Ba(NO₃)₂?

Answer

M(Ba(NO₃)₂) ≈

261.34 g/mol

Atomic weights: IUPAC standard values (CIAAW, 2024); the sum is rounded to the decimal places of the least precise one — Ba: 137.33.

Ba(NO₃)₂ = Ba + 2 × (N + 3 O) → Ba 1, N 2, O 6

Contribution of each element
Element	Atoms, n	Atomic weight, A	n × A, g/mol Mass fraction, w	Mass fraction, w
Babarium	1	137.33	137.33 w ≈ 52.55%	≈ 52.55%
Nnitrogen	2	14.007	28.014 w ≈ 10.72%	≈ 10.72%
Ooxygen	6	15.999	95.994 w ≈ 36.73%	≈ 36.73%
Σ = 261.338 ≈ 261.34 g/mol w = 100%				100%

Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

Mass fractions of the elements

Ba 52.55%O 36.73%

N 10.72%

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Molar masses of substances nearby

Formula	M, g/mol
I₂ (iodine)	253.80
S₈ (octasulfur)	256.48
C₆H₅Na₃O₇ (trisodium citrate)	258.069
Ba(NO₃)₂ (barium nitrate)	261.34
Na₂Cr₂O₇ (sodium dichromate)	261.965
Mg₃(PO₄)₂ (magnesium phosphate)	262.855
AlBr₃ (aluminum bromide)	266.694

FAQ

What is the molar mass of Ba(NO3)2?

M(Ba(NO₃)₂) ≈ 261.34 g/mol

How to calculate the molar mass of Ba(NO₃)₂?

Add up the atomic weights of all the atoms in the formula: 137.33 + 2 × 14.007 + 6 × 15.999 = 261.338 ≈ 261.34 g/mol.

How many grams are in 2 moles of Ba(NO₃)₂?

m = n × M = 2 mol × 261.34 g/mol = 522.68 g.

See Also