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    Molar Mass of BaBr2 (Barium Bromide)

    Molar Mass Calculator
    Chemical formula

    What is the molar mass of BaBr2?

    Answer

    M(BaBr2) ≈
    297.14 g/mol

    Atomic weights: IUPAC standard values (CIAAW, 2024); the sum is rounded to the decimal places of the least precise one — Ba: 137.33.

    Contribution of each element
    Element Atoms, n Atomic weight, A n × A, g/mol Mass fraction, w
    Babarium1137.33137.33 w ≈ 46.22%
    Brbromine279.904159.808 w ≈ 53.78%
    Σ = 297.138 ≈ 297.14 g/mol w = 100%

    Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

    Mass fractions of the elements

    Related Calculations

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    <a href="https://calculat.io/en/other/molar-mass/babr2">Molar Mass of BaBr2 (Barium Bromide): Step by Step</a>Copy
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    Molar Mass of BaBr2 (Barium Bromide): Step by Step. M(BaBr2) ≈ 297.14 g/mol: 137.33 (Ba) + 2 × 79.904 (Br). Mass fractions: Br 53.78%, Ba 46.22%.
    https://calculat.io/en/other/molar-mass/babr2/generated.jpgCopy

    Molar masses of substances nearby

    FormulaM, g/mol
    CaI₂ (calcium iodide)293.88
    K₂Cr₂O₇ (potassium dichromate)294.181
    HgSO₄ (mercuric sulfate)296.65
    BaBr₂ (barium bromide)297.14
    SbCl₅ (antimony pentachloride)299.01
    C₁₅H₁₀O₇ (quercetin)302.238
    PbSO₄ (lead sulfate)303.3
    Recalculate with different values ↑

    FAQ

    What is the molar mass of BaBr2?

    M(BaBr₂) ≈ 297.14 g/mol

    How to calculate the molar mass of BaBr₂?

    Add up the atomic weights of all the atoms in the formula: 137.33 + 2 × 79.904 = 297.138 ≈ 297.14 g/mol.

    How many grams are in 2 moles of BaBr₂?

    m = n × M = 2 mol × 297.14 g/mol = 594.28 g.

    See Also