Molar Mass of AgC10H9N4SO2

Molar Mass Calculator

What is the molar mass of AgC₁₀H₉N₄SO₂?

Answer

M(AgC₁₀H₉N₄SO₂) ≈

357.14 g/mol

Atomic weights: IUPAC standard values (CIAAW, 2024); the sum is rounded to the decimal places of the least precise one — Ag: 107.87, S: 32.06.

Contribution of each element
Element	Atoms, n	Atomic weight, A	n × A, g/mol Mass fraction, w	Mass fraction, w
Agsilver	1	107.87	107.87 w ≈ 30.20%	≈ 30.20%
Ccarbon	10	12.011	120.110 w ≈ 33.63%	≈ 33.63%
Hhydrogen	9	1.0080	9.0720 w ≈ 2.54%	≈ 2.54%
Nnitrogen	4	14.007	56.028 w ≈ 15.69%	≈ 15.69%
Ssulfur	1	32.06	32.06 w ≈ 8.98%	≈ 8.98%
Ooxygen	2	15.999	31.998 w ≈ 8.96%	≈ 8.96%
Σ = 357.138 ≈ 357.14 g/mol w = 100%				100%

Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

Mass fractions of the elements

C 33.63%Ag 30.20%N 15.69%S 8.98%O 8.96%H 2.54%

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Molar masses of substances nearby

Formula	M, g/mol
Pb(NO₃)₂ (lead(II) nitrate)	331.2
Al₂(SO₄)₃ (aluminium sulfate)	342.13
C₁₂H₂₂O₁₁ (sucrose)	342.297
AgC₁₀H₉N₄SO₂	357.14
Na₂B₄O₇·10H₂O	381.36
Zn₃(PO₄)₂ (zinc phosphate)	386.08
BaI₂ (barium iodide)	391.13

FAQ

What is the molar mass of AgC10H9N4SO2?

M(AgC₁₀H₉N₄SO₂) ≈ 357.14 g/mol

How to calculate the molar mass of AgC₁₀H₉N₄SO₂?

Add up the atomic weights of all the atoms in the formula: 107.87 + 10 × 12.011 + 9 × 1.0080 + 4 × 14.007 + 32.06 + 2 × 15.999 = 357.138 ≈ 357.14 g/mol.

How many grams are in 2 moles of AgC₁₀H₉N₄SO₂?

m = n × M = 2 mol × 357.14 g/mol = 714.28 g.

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