Molar Mass of Ag2CO3 (Silver Carbonate): Step by Step

What is the molar mass of Ag₂CO₃?

Answer

M(Ag₂CO₃) ≈

275.75 g/mol

Atomic weights: IUPAC standard values (CIAAW, 2024); the sum is rounded to the decimal places of the least precise one — Ag: 107.87.

Contribution of each element
Element	Atoms, n	Atomic weight, A	n × A, g/mol Mass fraction, w	Mass fraction, w
Agsilver	2	107.87	215.74 w ≈ 78.24%	≈ 78.24%
Ccarbon	1	12.011	12.011 w ≈ 4.36%	≈ 4.36%
Ooxygen	3	15.999	47.997 w ≈ 17.41%	≈ 17.41%
Σ = 275.748 ≈ 275.75 g/mol w = 100%				100%

Each fraction is rounded on its own, so the printed ones add up to 100.01%; unrounded, they make exactly 100%.

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Formula	M, g/mol
AlBr₃ (aluminum bromide)	266.694
PbCO₃ (lead carbonate)	267.2
HgCl₂ (mercuric chloride)	271.49
Ag₂CO₃ (silver carbonate)	275.75
FeSO₄·7H₂O (ferrous sulfate heptahydrate)	278.01
PbCl₂ (lead chloride)	278.1
MgI₂ (magnesium iodide)	278.11