Molar Mass of (NH4)2HPO4 (Dibasic Ammonium Phosphate)
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What is the molar mass of (NH4)2HPO4?
Answer
M((NH4)2HPO4) =
132.056 g/mol
Atomic weights: IUPAC standard values (CIAAW, 2024).
(NH4)2HPO4 = 2 × (N + 4 H) + H + P + 4 O → N 2, H 9, P 1, O 4
| Element | Atoms, n | Atomic weight, A | n × A, g/mol Mass fraction, w | |
|---|---|---|---|---|
| Nnitrogen | 2 | 14.007 | 28.014 w ≈ 21.21% | ≈ 21.21% |
| Hhydrogen | 9 | 1.0080 | 9.0720 w ≈ 6.87% | ≈ 6.87% |
| Pphosphorus | 1 | 30.974 | 30.974 w ≈ 23.46% | ≈ 23.46% |
| Ooxygen | 4 | 15.999 | 63.996 w ≈ 48.46% | ≈ 48.46% |
| Σ = 132.056 g/mol w = 100% | 100% | |||
Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)
O 48.46%
P 23.46%N 21.21%H 6.87%
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Molar masses of substances nearby
| Formula | M, g/mol |
|---|---|
| CoCl₂ (cobaltous chloride) | 129.83 |
| C₆H₁₀O₃ (ethyl acetoacetate) | 130.143 |
| Xe (xenon) | 131.29 |
| (NH₄)₂HPO₄ (dibasic ammonium phosphate) | 132.056 |
| (NH₄)₂SO₄ (ammonium sulfate) | 132.13 |
| Cs (caesium) | 132.91 |
| AlCl₃ (aluminum chloride) | 133.33 |