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    Molar Mass of Na2B4O7·10H2O

    Molar Mass Calculator
    Chemical formula

    What is the molar mass of Na2B4O7·10H2O?

    Answer

    M(Na2B4O7·10H2O) ≈
    381.36 g/mol

    Atomic weights: IUPAC standard values (CIAAW, 2024); the sum is rounded to the decimal places of the least precise one — B: 10.81.

    10 H2O — water of crystallization, part of the molar mass: 10 × 18.015 = 180.150.

    Na2B4O7·10H2O = Na2B4O7 + 10 H2O → Na 2, B 4, O 17, H 20

    Contribution of each element
    Element Atoms, n Atomic weight, A n × A, g/mol Mass fraction, w
    Nasodium222.99045.980 w ≈ 12.06%
    Bboron410.8143.24 w ≈ 11.34%
    Ooxygen1715.999271.983 w ≈ 71.32%
    Hhydrogen201.008020.1600 w ≈ 5.29%
    Σ = 381.363 ≈ 381.36 g/mol w = 100%

    Each fraction is rounded on its own, so the printed ones add up to 100.01%; unrounded, they make exactly 100%.

    Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

    Mass fractions of the elements

    Na 12.06%B 11.34%H 5.29%

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    Molar Mass of Na2B4O7·10H2O: Step by Step. M(Na2B4O7·10H2O) ≈ 381.36 g/mol: 2 × 22.990 (Na) + 4 × 10.81 (B) + 17 × 15.999 (O) + 20 × 1.0080 (H). Mass fractions: O 71.32%, Na 12.06%, B 11.34%.
    https://calculat.io/en/other/molar-mass/na2b4o7.10h2o/generated.jpgCopy

    FAQ

    What is the molar mass of Na2B4O7·10H2O?

    M(Na₂B₄O₇·10H₂O) ≈ 381.36 g/mol

    Is the water counted in Na₂B₄O₇·10H₂O?

    Yes: the water of crystallization is part of the formula and of the molar mass. 10 H₂O add 10 × 18.015 = 180.150 g/mol; M(Na₂B₄O₇·10H₂O) ≈ 381.36 g/mol, while anhydrous M(Na₂B₄O₇) ≈ 201.21 g/mol.

    How many grams are in 2 moles of Na₂B₄O₇·10H₂O?

    m = n × M = 2 mol × 381.36 g/mol = 762.72 g.