Molar Mass of (NH4)2S (Ammonium Sulfide)
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What is the molar mass of (NH4)2S?
Answer
M((NH4)2S) ≈
68.14 g/mol
Atomic weights: IUPAC standard values (CIAAW, 2024); the sum is rounded to the decimal places of the least precise one — S: 32.06.
(NH4)2S = 2 × (N + 4 H) + S → N 2, H 8, S 1
| Element | Atoms, n | Atomic weight, A | n × A, g/mol Mass fraction, w | |
|---|---|---|---|---|
| Nnitrogen | 2 | 14.007 | 28.014 w ≈ 41.11% | ≈ 41.11% |
| Hhydrogen | 8 | 1.0080 | 8.0640 w ≈ 11.83% | ≈ 11.83% |
| Ssulfur | 1 | 32.06 | 32.06 w ≈ 47.05% | ≈ 47.05% |
| Σ = 68.138 ≈ 68.14 g/mol w = 100% | 100% | |||
Each fraction is rounded on its own, so the printed ones add up to 99.99%; unrounded, they make exactly 100%.
Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)
S 47.05%N 41.11%
H 11.83%
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Molar masses of substances nearby
| Formula | M, g/mol |
|---|---|
| HCOONa (sodium formate) | 68.007 |
| C₃O₂ (carbon suboxide) | 68.031 |
| C₃H₄N₂ (imidazole) | 68.079 |
| (NH₄)₂S (ammonium sulfide) | 68.14 |
| LiNO₃ (lithium nitrate) | 68.94 |
| NaNO₂ (sodium nitrite) | 68.995 |
| B₂O₃ (diboron trioxide) | 69.62 |