Molar Mass of Zn3(PO4)2 (Zinc Phosphate)
Molar Mass Calculator
What is the molar mass of Zn3(PO4)2?
Answer
M(Zn3(PO4)2) =
386.08 g/mol
Atomic weights: IUPAC standard values (CIAAW, 2024).
Zn3(PO4)2 = 3 Zn + 2 × (P + 4 O) → Zn 3, P 2, O 8
| Element | Atoms, n | Atomic weight, A | n × A, g/mol Mass fraction, w | |
|---|---|---|---|---|
| Znzinc | 3 | 65.38 | 196.14 w ≈ 50.80% | ≈ 50.80% |
| Pphosphorus | 2 | 30.974 | 61.948 w ≈ 16.05% | ≈ 16.05% |
| Ooxygen | 8 | 15.999 | 127.992 w ≈ 33.15% | ≈ 33.15% |
| Σ = 386.08 g/mol w = 100% | 100% | |||
Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)
Zn 50.80%
O 33.15%P 16.05%
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Molar masses of substances nearby
| Formula | M, g/mol |
|---|---|
| C₁₂H₂₂O₁₁ (sucrose) | 342.297 |
| AgC₁₀H₉N₄SO₂ | 357.14 |
| Na₂B₄O₇·10H₂O | 381.36 |
| Zn₃(PO₄)₂ (zinc phosphate) | 386.08 |
| BaI₂ (barium iodide) | 391.13 |
| Cr₂(SO₄)₃ (chromium(III) sulfate) | 392.16 |
| CHI₃ (iodoform) | 393.72 |