Molar Mass of Ag2CO3 (Silver Carbonate)
Molar Mass Calculator
What is the molar mass of Ag2CO3?
Answer
M(Ag2CO3) ≈
275.75 g/mol
Atomic weights: IUPAC standard values (CIAAW, 2024); the sum is rounded to the decimal places of the least precise one — Ag: 107.87.
| Element | Atoms, n | Atomic weight, A | n × A, g/mol Mass fraction, w | |
|---|---|---|---|---|
| Agsilver | 2 | 107.87 | 215.74 w ≈ 78.24% | ≈ 78.24% |
| Ccarbon | 1 | 12.011 | 12.011 w ≈ 4.36% | ≈ 4.36% |
| Ooxygen | 3 | 15.999 | 47.997 w ≈ 17.41% | ≈ 17.41% |
| Σ = 275.748 ≈ 275.75 g/mol w = 100% | 100% | |||
Each fraction is rounded on its own, so the printed ones add up to 100.01%; unrounded, they make exactly 100%.
Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)
Ag 78.24%
O 17.41%C 4.36%
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FAQ
What is the molar mass of Ag2CO3?
M(Ag₂CO₃) ≈ 275.75 g/mol
How to calculate the molar mass of Ag₂CO₃?
Add up the atomic weights of all the atoms in the formula: 2 × 107.87 + 12.011 + 3 × 15.999 = 275.748 ≈ 275.75 g/mol.
How many grams are in 2 moles of Ag₂CO₃?
m = n × M = 2 mol × 275.75 g/mol = 551.50 g.
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