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    Molar Mass of (CH3COO)2Zn (Zinc Acetate)

    Molar Mass Calculator
    Chemical formula

    What is the molar mass of (CH3COO)2Zn?

    Answer

    M((CH3COO)2Zn) ≈
    183.47 g/mol

    Atomic weights: IUPAC standard values (CIAAW, 2024); the sum is rounded to the decimal places of the least precise one — Zn: 65.38.

    (CH3COO)2Zn = 2 × (C + 3 H + C + O + O) + Zn → C 4, H 6, O 4, Zn 1

    Contribution of each element
    Element Atoms, n Atomic weight, A n × A, g/mol Mass fraction, w
    Ccarbon412.01148.044 w ≈ 26.19%
    Hhydrogen61.00806.0480 w ≈ 3.30%
    Ooxygen415.99963.996 w ≈ 34.88%
    Znzinc165.3865.38 w ≈ 35.64%
    Σ = 183.468 ≈ 183.47 g/mol w = 100%

    Each fraction is rounded on its own, so the printed ones add up to 100.01%; unrounded, they make exactly 100%.

    Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

    Mass fractions of the elements

    O 34.88%C 26.19%H 3.30%

    See Also

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    <a href="https://calculat.io/en/other/molar-mass/%28ch3coo%292zn">Molar Mass of (CH3COO)2Zn (Zinc Acetate): Step by Step</a>Copy
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    Molar Mass of (CH3COO)2Zn (Zinc Acetate): Step by Step. M((CH3COO)2Zn) ≈ 183.47 g/mol: 4 × 12.011 (C) + 6 × 1.0080 (H) + 4 × 15.999 (O) + 65.38 (Zn). Mass fractions: Zn 35.64%, O 34.88%, C 26.19%.
    https://calculat.io/en/other/molar-mass/%28ch3coo%292zn/generated.jpgCopy