Molar Mass of (CH3COO)2Pb (Lead(II) Acetate): Step by Step

What is the molar mass of (CH₃COO)₂Pb?

Answer

M((CH₃COO)₂Pb) ≈

325.3 g/mol

Atomic weights: IUPAC standard values (CIAAW, 2024); the sum is rounded to the decimal places of the least precise one — Pb: 207.2.

(CH₃COO)₂Pb = 2 × (C + 3 H + C + O + O) + Pb → C 4, H 6, O 4, Pb 1

Contribution of each element
Element	Atoms, n	Atomic weight, A	n × A, g/mol Mass fraction, w	Mass fraction, w
Ccarbon	4	12.011	48.044 w ≈ 14.77%	≈ 14.77%
Hhydrogen	6	1.0080	6.0480 w ≈ 1.86%	≈ 1.86%
Ooxygen	4	15.999	63.996 w ≈ 19.67%	≈ 19.67%
Pblead	1	207.2	207.2 w ≈ 63.70%	≈ 63.70%
Σ = 325.288 ≈ 325.3 g/mol w = 100%				100%

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Formula	M, g/mol
Na₂SO₄·10H₂O (sodium sulfate decahydrate)	322.19
PbCrO₄ (lead(II) chromate)	323.2
Hg(NO₃)₂ (mercuric nitrate)	324.60
(CH₃COO)₂Pb (lead(II) acetate)	325.3
CCs₂O₃ (cesium carbonate)	325.83
Pb(NO₃)₂ (lead(II) nitrate)	331.2
Al₂(SO₄)₃ (aluminium sulfate)	342.13