Molar Mass of (NH4)2S (Ammonium Sulfide)

Molar Mass Calculator

What is the molar mass of (NH₄)₂S?

Answer

M((NH₄)₂S) ≈

68.14 g/mol

Atomic weights: IUPAC standard values (CIAAW, 2024); the sum is rounded to the decimal places of the least precise one — S: 32.06.

(NH₄)₂S = 2 × (N + 4 H) + S → N 2, H 8, S 1

Contribution of each element
Element	Atoms, n	Atomic weight, A	n × A, g/mol Mass fraction, w	Mass fraction, w
Nnitrogen	2	14.007	28.014 w ≈ 41.11%	≈ 41.11%
Hhydrogen	8	1.0080	8.0640 w ≈ 11.83%	≈ 11.83%
Ssulfur	1	32.06	32.06 w ≈ 47.05%	≈ 47.05%
Σ = 68.138 ≈ 68.14 g/mol w = 100%				100%

Each fraction is rounded on its own, so the printed ones add up to 99.99%; unrounded, they make exactly 100%.

Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

Mass fractions of the elements

S 47.05%N 41.11%

H 11.83%

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Molar masses of substances nearby

Formula	M, g/mol
HCOONa (sodium formate)	68.007
C₃O₂ (carbon suboxide)	68.031
C₃H₄N₂ (imidazole)	68.079
(NH₄)₂S (ammonium sulfide)	68.14
LiNO₃ (lithium nitrate)	68.94
NaNO₂ (sodium nitrite)	68.995
B₂O₃ (diboron trioxide)	69.62

FAQ

What is the molar mass of (NH4)2S?

M((NH₄)₂S) ≈ 68.14 g/mol

How to calculate the molar mass of (NH₄)₂S?

Add up the atomic weights of all the atoms in the formula: 2 × 14.007 + 8 × 1.0080 + 32.06 = 68.138 ≈ 68.14 g/mol.

How many grams are in 2 moles of (NH₄)₂S?

m = n × M = 2 mol × 68.14 g/mol = 136.28 g.

See Also