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    Molar Mass of C3H4N2 (Imidazole)

    Molar Mass Calculator
    Chemical formula

    What is the molar mass of C3H4N2?

    Answer

    M(C3H4N2) =
    68.079 g/mol

    Atomic weights: IUPAC standard values (CIAAW, 2024).

    Contribution of each element
    Element Atoms, n Atomic weight, A n × A, g/mol Mass fraction, w
    Ccarbon312.01136.033 w ≈ 52.93%
    Hhydrogen41.00804.0320 w ≈ 5.92%
    Nnitrogen214.00728.014 w ≈ 41.15%
    Σ = 68.079 g/mol w = 100%

    Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

    Mass fractions of the elements

    H 5.92%

    Related Calculations

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    Molar Mass of C3H4N2 (Imidazole): Step by Step. M(C3H4N2) = 68.079 g/mol: 3 × 12.011 (C) + 4 × 1.0080 (H) + 2 × 14.007 (N). Mass fractions: C 52.93%, N 41.15%, H 5.92%.
    https://calculat.io/en/other/molar-mass/c3h4n2/generated.jpgCopy

    Molar masses of substances nearby

    FormulaM, g/mol
    Zn (zinc)65.38
    HCOONa (sodium formate)68.007
    C₃O₂ (carbon suboxide)68.031
    C₃H₄N₂ (imidazole)68.079
    (NH₄)₂S (ammonium sulfide)68.14
    LiNO₃ (lithium nitrate)68.94
    NaNO₂ (sodium nitrite)68.995
    Recalculate with different values ↑

    FAQ

    What is the molar mass of C3H4N2?

    M(C₃H₄N₂) = 68.079 g/mol

    How to calculate the molar mass of C₃H₄N₂?

    Add up the atomic weights of all the atoms in the formula: 3 × 12.011 + 4 × 1.0080 + 2 × 14.007 = 68.079 g/mol.

    How many grams are in 2 moles of C₃H₄N₂?

    m = n × M = 2 mol × 68.079 g/mol = 136.158 g.

    See Also