Molar Mass of Pb(NO3)2 (Lead(II) Nitrate)

Molar Mass Calculator

What is the molar mass of Pb(NO₃)₂?

Answer

M(Pb(NO₃)₂) ≈

331.2 g/mol

Atomic weights: IUPAC standard values (CIAAW, 2024); the sum is rounded to the decimal places of the least precise one — Pb: 207.2.

Pb(NO₃)₂ = Pb + 2 × (N + 3 O) → Pb 1, N 2, O 6

Contribution of each element
Element	Atoms, n	Atomic weight, A	n × A, g/mol Mass fraction, w	Mass fraction, w
Pblead	1	207.2	207.2 w ≈ 62.56%	≈ 62.56%
Nnitrogen	2	14.007	28.014 w ≈ 8.46%	≈ 8.46%
Ooxygen	6	15.999	95.994 w ≈ 28.98%	≈ 28.98%
Σ = 331.208 ≈ 331.2 g/mol w = 100%				100%

Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

Mass fractions of the elements

Pb 62.56%

O 28.98%N 8.46%

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Molar masses of substances nearby

Formula	M, g/mol
Hg(NO₃)₂ (mercuric nitrate)	324.60
(CH₃COO)₂Pb (lead(II) acetate)	325.3
CCs₂O₃ (cesium carbonate)	325.83
Pb(NO₃)₂ (lead(II) nitrate)	331.2
Al₂(SO₄)₃ (aluminium sulfate)	342.13
C₁₂H₂₂O₁₁ (sucrose)	342.297
AgC₁₀H₉N₄SO₂	357.14

FAQ

What is the molar mass of Pb(NO3)2?

M(Pb(NO₃)₂) ≈ 331.2 g/mol

How to calculate the molar mass of Pb(NO₃)₂?

Add up the atomic weights of all the atoms in the formula: 207.2 + 2 × 14.007 + 6 × 15.999 = 331.208 ≈ 331.2 g/mol.

How many grams are in 2 moles of Pb(NO₃)₂?

m = n × M = 2 mol × 331.2 g/mol = 662.4 g.

See Also