Molar Mass of MgCO3 (Magnesium Carbonate)

Molar Mass Calculator

What is the molar mass of MgCO₃?

Answer

M(MgCO₃) =

84.313 g/mol

Atomic weights: IUPAC standard values (CIAAW, 2024).

Contribution of each element
Element	Atoms, n	Atomic weight, A	n × A, g/mol Mass fraction, w	Mass fraction, w
Mgmagnesium	1	24.305	24.305 w ≈ 28.83%	≈ 28.83%
Ccarbon	1	12.011	12.011 w ≈ 14.25%	≈ 14.25%
Ooxygen	3	15.999	47.997 w ≈ 56.93%	≈ 56.93%
Σ = 84.313 g/mol w = 100%				100%

Each fraction is rounded on its own, so the printed ones add up to 100.01%; unrounded, they make exactly 100%.

Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

Mass fractions of the elements

O 56.93%

Mg 28.83%C 14.25%

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Molar masses of substances nearby

Formula	M, g/mol
NaHCO₃ (sodium bicarbonate)	84.006
CHKO₂ (potassium formate)	84.115
C₆H₁₂ (cyclohexane)	84.162
MgCO₃ (magnesium carbonate)	84.313
HClO₃ (chloric acid)	84.46
CH₂Cl₂ (dichloromethane)	84.93
NaNO₃ (sodium nitrate)	84.994

FAQ

What is the molar mass of MgCO3?

M(MgCO₃) = 84.313 g/mol

How to calculate the molar mass of MgCO₃?

Add up the atomic weights of all the atoms in the formula: 24.305 + 12.011 + 3 × 15.999 = 84.313 g/mol.

How many grams are in 2 moles of MgCO₃?

m = n × M = 2 mol × 84.313 g/mol = 168.626 g.

See Also