Molar Mass of Mn(NO3)2 (Manganese Nitrate)
Molar Mass Calculator
What is the molar mass of Mn(NO3)2?
Answer
M(Mn(NO3)2) =
178.946 g/mol
Atomic weights: IUPAC standard values (CIAAW, 2024).
Mn(NO3)2 = Mn + 2 × (N + 3 O) → Mn 1, N 2, O 6
| Element | Atoms, n | Atomic weight, A | n × A, g/mol Mass fraction, w | |
|---|---|---|---|---|
| Mnmanganese | 1 | 54.938 | 54.938 w ≈ 30.70% | ≈ 30.70% |
| Nnitrogen | 2 | 14.007 | 28.014 w ≈ 15.66% | ≈ 15.66% |
| Ooxygen | 6 | 15.999 | 95.994 w ≈ 53.64% | ≈ 53.64% |
| Σ = 178.946 g/mol w = 100% | 100% | |||
Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)
O 53.64%
Mn 30.70%N 15.66%
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Molar masses of substances nearby
| Formula | M, g/mol |
|---|---|
| BaF₂ (barium fluoride) | 175.33 |
| HC₆H₇O₆ (vitamin C) | 176.124 |
| Hf (hafnium) | 178.49 |
| Mn(NO₃)₂ (manganese nitrate) | 178.946 |
| C₆H₁₂O₆ (glucose) | 180.156 |
| C₉H₈O₄ (aspirin) | 180.159 |
| Ta (tantalum) | 180.95 |