Molar Mass of MgBr2 (Magnesium Bromide)

Molar Mass Calculator

What is the molar mass of MgBr₂?

Answer

M(MgBr₂) =

184.113 g/mol

Atomic weights: IUPAC standard values (CIAAW, 2024).

Contribution of each element
Element	Atoms, n	Atomic weight, A	n × A, g/mol Mass fraction, w	Mass fraction, w
Mgmagnesium	1	24.305	24.305 w ≈ 13.20%	≈ 13.20%
Brbromine	2	79.904	159.808 w ≈ 86.80%	≈ 86.80%
Σ = 184.113 g/mol w = 100%				100%

Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

Mass fractions of the elements

Br 86.80%

Mg 13.20%

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Molar masses of substances nearby

Formula	M, g/mol
CuFeS₂	183.51
SrSO₄ (strontium sulfate)	183.68
W (tungsten)	183.84
MgBr₂ (magnesium bromide)	184.113
Re (rhenium)	186.21
Cu(NO₃)₂ (copper(II) nitrate)	187.554
AgBr (silver bromide)	187.77

FAQ

What is the molar mass of MgBr2?

M(MgBr₂) = 184.113 g/mol

How to calculate the molar mass of MgBr₂?

Add up the atomic weights of all the atoms in the formula: 24.305 + 2 × 79.904 = 184.113 g/mol.

How many grams are in 2 moles of MgBr₂?

m = n × M = 2 mol × 184.113 g/mol = 368.226 g.

See Also