Molar Mass of C16H9N4Na3O9S2 (Tartrazine)
Molar Mass Calculator
What is the molar mass of C16H9N4Na3O9S2?
Answer
M(C16H9N4Na3O9S2) ≈
534.36 g/mol
Atomic weights: IUPAC standard values (CIAAW, 2024); the sum is rounded to the decimal places of the least precise one — S: 32.06.
| Element | Atoms, n | Atomic weight, A | n × A, g/mol Mass fraction, w | |
|---|---|---|---|---|
| Ccarbon | 16 | 12.011 | 192.176 w ≈ 35.96% | ≈ 35.96% |
| Hhydrogen | 9 | 1.0080 | 9.0720 w ≈ 1.70% | ≈ 1.70% |
| Nnitrogen | 4 | 14.007 | 56.028 w ≈ 10.49% | ≈ 10.49% |
| Nasodium | 3 | 22.990 | 68.970 w ≈ 12.91% | ≈ 12.91% |
| Ooxygen | 9 | 15.999 | 143.991 w ≈ 26.95% | ≈ 26.95% |
| Ssulfur | 2 | 32.06 | 64.12 w ≈ 12.00% | ≈ 12.00% |
| Σ = 534.357 ≈ 534.36 g/mol w = 100% | 100% | |||
Each fraction is rounded on its own, so the printed ones add up to 100.01%; unrounded, they make exactly 100%.
Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)
C 35.96%
O 26.95%Na 12.91%S 12.00%N 10.49%H 1.70%
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FAQ
What is the molar mass of C16H9N4Na3O9S2?
M(C₁₆H₉N₄Na₃O₉S₂) ≈ 534.36 g/mol
How to calculate the molar mass of C₁₆H₉N₄Na₃O₉S₂?
Add up the atomic weights of all the atoms in the formula: 16 × 12.011 + 9 × 1.0080 + 4 × 14.007 + 3 × 22.990 + 9 × 15.999 + 2 × 32.06 = 534.357 ≈ 534.36 g/mol.
How many grams are in 2 moles of C₁₆H₉N₄Na₃O₉S₂?
m = n × M = 2 mol × 534.36 g/mol = 1,068.72 g.
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- Молярная масса C16H9N4Na3O9S2 (тартразин): расчёт
- Masa molar de C16H9N4Na3O9S2 (tartracina): cálculo
- Massa molar de C16H9N4Na3O9S2 (tartrazina): cálculo