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    Molar Mass of Na2CO3·10H2O (Sodium Carbonate Decahydrate)

    Molar Mass Calculator
    Chemical formula

    What is the molar mass of Na2CO3·10H2O?

    Answer

    M(Na2CO3·10H2O) =
    286.138 g/mol

    Atomic weights: IUPAC standard values (CIAAW, 2024).

    10 H2O — water of crystallization, part of the molar mass: 10 × 18.015 = 180.150.

    Na2CO3·10H2O = Na2CO3 + 10 H2O → Na 2, C 1, O 13, H 20

    Contribution of each element
    Element Atoms, n Atomic weight, A n × A, g/mol Mass fraction, w
    Nasodium222.99045.980 w ≈ 16.07%
    Ccarbon112.01112.011 w ≈ 4.20%
    Ooxygen1315.999207.987 w ≈ 72.69%
    Hhydrogen201.008020.1600 w ≈ 7.05%
    Σ = 286.138 g/mol w = 100%

    Each fraction is rounded on its own, so the printed ones add up to 100.01%; unrounded, they make exactly 100%.

    Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

    Mass fractions of the elements

    Na 16.07%H 7.05%C 4.20%

    See Also

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    Molar Mass of Na2CO3·10H2O (Sodium Carbonate Decahydrate). M(Na2CO3·10H2O) = 286.138 g/mol: 2 × 22.990 (Na) + 12.011 (C) + 13 × 15.999 (O) + 20 × 1.0080 (H). Mass fractions: O 72.69%, Na 16.07%, H 7.05%.
    https://calculat.io/en/other/molar-mass/na2co3.10h2o/generated.jpgCopy

    FAQ

    What is the molar mass of Na2CO3·10H2O?

    M(Na₂CO₃·10H₂O) = 286.138 g/mol

    Is the water counted in Na₂CO₃·10H₂O?

    Yes: the water of crystallization is part of the formula and of the molar mass. 10 H₂O add 10 × 18.015 = 180.150 g/mol; M(Na₂CO₃·10H₂O) = 286.138 g/mol, while anhydrous M(Na₂CO₃) = 105.988 g/mol.

    How many grams are in 2 moles of Na₂CO₃·10H₂O?

    m = n × M = 2 mol × 286.138 g/mol = 572.276 g.