Molar Mass of Ba3(PO4)2 (Barium Phosphate)

Molar Mass Calculator

What is the molar mass of Ba₃(PO₄)₂?

Answer

M(Ba₃(PO₄)₂) =

601.93 g/mol

Atomic weights: IUPAC standard values (CIAAW, 2024).

Ba₃(PO₄)₂ = 3 Ba + 2 × (P + 4 O) → Ba 3, P 2, O 8

Contribution of each element
Element	Atoms, n	Atomic weight, A	n × A, g/mol Mass fraction, w	Mass fraction, w
Babarium	3	137.33	411.99 w ≈ 68.44%	≈ 68.44%
Pphosphorus	2	30.974	61.948 w ≈ 10.29%	≈ 10.29%
Ooxygen	8	15.999	127.992 w ≈ 21.26%	≈ 21.26%
Σ = 601.93 g/mol w = 100%				100%

Each fraction is rounded on its own, so the printed ones add up to 99.99%; unrounded, they make exactly 100%.

Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

Mass fractions of the elements

Ba 68.44%

O 21.26%P 10.29%

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Molar masses of substances nearby

Formula	M, g/mol
C₁₂H₂₂CaO₁₄ (calcium gluconate)	430.372
HgI₂ (mercury(II) iodide)	454.39
PbI₂ (lead(II) iodide)	461.0
C₁₆H₉N₄Na₃O₉S₂ (tartrazine)	534.36
Ba₃(PO₄)₂ (barium phosphate)	601.93
C₂₇H₂₈Br₂O₅S (bromthymol blue)	624.38
C₅₇H₁₁₀O₆ (glyceryl tristearate)	891.501

FAQ

What is the molar mass of Ba3(PO4)2?

M(Ba₃(PO₄)₂) = 601.93 g/mol

How to calculate the molar mass of Ba₃(PO₄)₂?

Add up the atomic weights of all the atoms in the formula: 3 × 137.33 + 2 × 30.974 + 8 × 15.999 = 601.93 g/mol.

How many grams are in 2 moles of Ba₃(PO₄)₂?

m = n × M = 2 mol × 601.93 g/mol = 1,203.86 g.

See Also