Molar Mass of Ag2SO4 (Silver Sulfate)

Molar Mass Calculator

What is the molar mass of Ag₂SO₄?

Answer

M(Ag₂SO₄) ≈

311.80 g/mol

Atomic weights: IUPAC standard values (CIAAW, 2024); the sum is rounded to the decimal places of the least precise one — Ag: 107.87, S: 32.06.

Contribution of each element
Element	Atoms, n	Atomic weight, A	n × A, g/mol Mass fraction, w	Mass fraction, w
Agsilver	2	107.87	215.74 w ≈ 69.19%	≈ 69.19%
Ssulfur	1	32.06	32.06 w ≈ 10.28%	≈ 10.28%
Ooxygen	4	15.999	63.996 w ≈ 20.52%	≈ 20.52%
Σ = 311.796 ≈ 311.80 g/mol w = 100%				100%

Each fraction is rounded on its own, so the printed ones add up to 99.99%; unrounded, they make exactly 100%.

Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

Mass fractions of the elements

Ag 69.19%

O 20.52%S 10.28%

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Molar masses of substances nearby

Formula	M, g/mol
PbSO₄ (lead sulfate)	303.3
Ba(ClO₃)₂ (barium chlorate)	304.22
Ca₃(PO₄)₂ (tricalcium phosphate)	310.174
Ag₂SO₄ (silver sulfate)	311.80
C₂₀H₁₄O₄ (phenolphthalein)	318.328
ZnI₂ (zinc iodide)	319.18
C₁₆H₁₈ClN₃S (methylene blue)	319.85

FAQ

What is the molar mass of Ag2SO4?

M(Ag₂SO₄) ≈ 311.80 g/mol

How to calculate the molar mass of Ag₂SO₄?

Add up the atomic weights of all the atoms in the formula: 2 × 107.87 + 32.06 + 4 × 15.999 = 311.796 ≈ 311.80 g/mol.

How many grams are in 2 moles of Ag₂SO₄?

m = n × M = 2 mol × 311.80 g/mol = 623.60 g.

See Also