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    Molar Mass of Ca3(PO4)2 (Tricalcium Phosphate)

    Molar Mass Calculator
    Chemical formula

    What is the molar mass of Ca3(PO4)2?

    Answer

    M(Ca3(PO4)2) =
    310.174 g/mol

    Atomic weights: IUPAC standard values (CIAAW, 2024).

    Ca3(PO4)2 = 3 Ca + 2 × (P + 4 O) → Ca 3, P 2, O 8

    Contribution of each element
    Element Atoms, n Atomic weight, A n × A, g/mol Mass fraction, w
    Cacalcium340.078120.234 w ≈ 38.76%
    Pphosphorus230.97461.948 w ≈ 19.97%
    Ooxygen815.999127.992 w ≈ 41.26%
    Σ = 310.174 g/mol w = 100%

    Each fraction is rounded on its own, so the printed ones add up to 99.99%; unrounded, they make exactly 100%.

    Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

    Mass fractions of the elements

    P 19.97%

    See Also

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    <a href="https://calculat.io/en/other/molar-mass/ca3%28po4%292">Molar Mass of Ca3(PO4)2 (Tricalcium Phosphate): Step by Step</a>Copy
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    Molar Mass of Ca3(PO4)2 (Tricalcium Phosphate): Step by Step. M(Ca3(PO4)2) = 310.174 g/mol: 3 × 40.078 (Ca) + 2 × 30.974 (P) + 8 × 15.999 (O). Mass fractions: O 41.26%, Ca 38.76%, P 19.97%.
    https://calculat.io/en/other/molar-mass/ca3%28po4%292/generated.jpgCopy

    FAQ

    What is the molar mass of Ca3(PO4)2?

    M(Ca₃(PO₄)₂) = 310.174 g/mol

    How to calculate the molar mass of Ca₃(PO₄)₂?

    Add up the atomic weights of all the atoms in the formula: 3 × 40.078 + 2 × 30.974 + 8 × 15.999 = 310.174 g/mol.

    How many grams are in 2 moles of Ca₃(PO₄)₂?

    m = n × M = 2 mol × 310.174 g/mol = 620.348 g.