Molar Mass of (NH4)2HPO4 (Dibasic Ammonium Phosphate)

Molar Mass Calculator

What is the molar mass of (NH₄)₂HPO₄?

Answer

M((NH₄)₂HPO₄) =

132.056 g/mol

Atomic weights: IUPAC standard values (CIAAW, 2024).

(NH₄)₂HPO₄ = 2 × (N + 4 H) + H + P + 4 O → N 2, H 9, P 1, O 4

Contribution of each element
Element	Atoms, n	Atomic weight, A	n × A, g/mol Mass fraction, w	Mass fraction, w
Nnitrogen	2	14.007	28.014 w ≈ 21.21%	≈ 21.21%
Hhydrogen	9	1.0080	9.0720 w ≈ 6.87%	≈ 6.87%
Pphosphorus	1	30.974	30.974 w ≈ 23.46%	≈ 23.46%
Ooxygen	4	15.999	63.996 w ≈ 48.46%	≈ 48.46%
Σ = 132.056 g/mol w = 100%				100%

Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

Mass fractions of the elements

O 48.46%

P 23.46%N 21.21%H 6.87%

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Molar masses of substances nearby

Formula	M, g/mol
CoCl₂ (cobaltous chloride)	129.83
C₆H₁₀O₃ (ethyl acetoacetate)	130.143
Xe (xenon)	131.29
(NH₄)₂HPO₄ (dibasic ammonium phosphate)	132.056
(NH₄)₂SO₄ (ammonium sulfate)	132.13
Cs (caesium)	132.91
AlCl₃ (aluminum chloride)	133.33

FAQ

What is the molar mass of (NH4)2HPO4?

M((NH₄)₂HPO₄) = 132.056 g/mol

How to calculate the molar mass of (NH₄)₂HPO₄?

Add up the atomic weights of all the atoms in the formula: 2 × 14.007 + 9 × 1.0080 + 30.974 + 4 × 15.999 = 132.056 g/mol.

How many grams are in 2 moles of (NH₄)₂HPO₄?

m = n × M = 2 mol × 132.056 g/mol = 264.112 g.

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